00:01
Okay, so when you react one phenopropine with hbr, you get one bromoproponzinzine as the sole product.
00:12
Well, technically, this is a chirocenter, so you're going to get, well, i won't get there yet.
00:17
So we have to propose a mechanism and explain why none of the other regional isomers are produced.
00:23
This kind of feels like a question you could have answered in a previous chapter when you learned about benzene in general.
00:30
So a lot of the same chemistry that happens with double bonds can happen with aline and allelic bonds, but it could also happen with benzene and benzol positions, right? so if you have, you can, now that you've learned more about benzene, you can introduce benzene as a substituent, and they're familiar with the benzodia bensal carbocadion being more stable than tertiary, being similar stability to an owl cat ion just based off of the bond dissociation -free energies that were in chapter four.
01:06
That was a previous question.
01:07
That's the only reason.
01:08
That was a previous question in this chapter.
01:10
That's the only reason why i bring it up here.
01:13
So why is this the only product? well, let's think about the mechanism, right? so this is essentially electrophilic addition of hbr.
01:22
So you know that you're not going to break rheumaticity, even though this is a strong acid.
01:28
So if you're going to protonate something, what are you going to protonate? your molecule is made entirely of carbon and hydrogen.
01:34
Where is the most electrophilic site on that carbon, on this molecule? right.
01:40
So protonating at this position right here would break that pie bonds.
01:47
That would give you a carbocation here.
01:55
That just gives you a secondary carbocation.
01:58
That's kind of boring.
01:59
So that's okay.
02:00
Let's weigh the options here.
02:02
So you can only protonate either of those two carbons.
02:05
So let's protonate the other one.
02:07
So you'll get a secondary carbocadion in that case...