We can do this by writing the limit as $e$ raised to the power of the limit of the natural logarithm of the expression. This gives us:
\[
\lim _{x \rightarrow 0}\left(\frac{\tan x}{x}\right)^{1 / x} = e^{\lim _{x \rightarrow 0} \frac{\ln(\tan x / x)}{x}}
\]
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