00:01
For this problem on the topic of force and motion, we are told that a ride consists of a car moving on a vertical circle at the end of a rigid boom.
00:07
The combined weight of the car and riders is 5 kiloons and it moves in a circle of radius 10 meters.
00:14
At the top of the circle, we want to know the magnitude of fb and its direction if the car's speed is 5 meters per second.
00:21
We then want to find fb in the direction if v is equal to 12 meters per second.
00:28
Now the force of the boom on the car is fb, which is capable of pointing in any direction.
00:34
We'll assume it to be upward as we apply newton's second law to the car, which is a total weight of 5 ,000 newtons.
00:41
And so newton's second law tells us that fb minus the weight w is equal to the mass of the car and riders, m times acceleration a.
00:51
But m is w over g, and a is minus v squared over r...