00:01
Okay, so for this question, they tell us the q or the amount of heat absorbed is 1 .85 kilojoules.
00:08
They tell us the mass is 0 .5 kilograms.
00:11
They tell us the final temperature is 37 degrees celsius.
00:15
And in order to solve this question, we just got to look up the specific heat.
00:18
We can look it up in the textbook or online, and we should get 3 .85 joules per gram times kelvin for a block of copper, right? and we want to find out what the final temperature is.
00:32
Oh no, we want to find out what the initial temperature is.
00:36
Initial temperature, right? so we need to use this equation.
00:38
Q is equal to m c times it by delta t.
00:45
Right, m is mass c is the specific heat capacity.
00:48
Delta t is the change of temperature and q is the amount of heat.
00:52
So we see this constant right here.
00:57
The units is joules per gram times kelvin so we need to convert celsius to kelvin, kilojoules to joules, and kilograms to grams, right? so, we know that one kilojoules is equal to a thousand joules.
01:12
So all we got to do is multiply 1 .85 times a thousand, right? or we can just put equals 1 .85 times 10 to the third, right? so, jewels, let me rewrite the 5.
01:28
1 .85...