00:01
So james bond is jumping off the bridge.
00:04
The bridge is 15 meters above the ground.
00:09
However, the truck that james bond is trying to jump on is 3 .5 meters above the ground.
00:15
So the net delta y is going to be 15 minus 3 .5.
00:19
So this will be 11 .5 meters.
00:22
We have a velocity of the truck 25 meters per second.
00:28
And so we need to find out how, how long it's going to take for this for him to drop 11 .5 meters.
00:37
So we can say that y final equals y initial plus vy initial t plus one half gt squared.
00:46
We know that b y initial and y initial both equal zero.
00:51
So we can say that t is going to be equal to the square root of two y final divided by g and this is going to equal 2 times 11 .5 divided by 9 .8.
01:09
And it takes james bond 1 .532 seconds to jump from the bridge and reach the top of the truck.
01:21
So delta x is going to be equal to 25 meters per second, the speed of the truck times 1 .532 seconds.
01:32
The time it takes for james bond to fall from the bridge to the top of the truck.
01:40
And then we're going to say one pole, one telephone pole for every 25 meters...