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Problem number 95.
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Here is first heated in a heating section and then pass through a vaporative cooler.
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The exit relative humidity and the amount of water added are to be determined.
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Here, firstly, we will draw a simple diagram so that our question may be resolved easily.
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First portion, heating coils, heating portion, second portion, water humidity, where water sprinkles as the air enters at 1 atmospheric 20 degree centigrade and 50 % relative humidity.
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When passed through evaporative cooler, its inlet is 35 degree and exhaust is 25 degree centigrade.
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Now coming towards part number a where we have to determine the exit relative humidity.
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From the psychometric chart, we will obtain w1 which comes out 0 .00726 kilogram of water, divisible by kilogram of dry air.
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This specific humidity omega remains constant during the heating process.
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Therefore, omega 2 is equal to omega 1, which is 0 .00726...