00:01
So before we solve this problem, we need to know two basic things, vapor pressure and the ideal gas law.
00:07
So vapor pressure is essentially the pressure exerted by a vapor when it's at thermodynamic equilibrium.
00:16
So when it's at a constant temperature.
00:20
Now this is the amount of pressure that it would exert in its environment, in a solution.
00:24
So say you have air, there's water vapor in the air.
00:27
That vapor is going to exert a certain pressure on its environment when it's in the air.
00:35
And the ideal gas law, the equation associated with it, is pv equals nrt.
00:45
This is used to determine the behavior of a substance or a gas in this case under specific conditions.
00:55
Okay, set with that out of the way, let's begin to solve the problem.
00:58
So let's write down what we know.
01:00
So we know the room dimensions.
01:04
That's useful.
01:05
So our room dimensions are 6 meters times 10 meters times 2 .2 meters.
01:16
Multiplying these three dimensions gives you the volume.
01:19
So you just multiply those together and you would get 132 meters cubed, which would be about 132 ,000 liters.
01:42
Okay? so that's the volume.
01:45
And we also know the temperature of the room, which is 30 degrees celsius.
01:50
Now when it comes to the ideal gas law, you always want to convert the temperature into kelvin.
01:55
So in order to convert celsius to kelvin, we just have to add 273.
02:02
So 273 plus 30 gives us 303 kelvin.
02:10
And we also know the vapor pressure, which is at this temperature, 85 % of what it would be at room temperature.
02:19
So all we need to do is just take our vapor pressure, which we know to be 31 .8 tor, and we just multiply it by 0 .85, or 85 over 100 if you prefer fractions.
02:41
You multiply that, and we get 27 .03 tor.
02:48
All right, so we have the volume, the temperature, and the pressure.
02:57
Now all these three values are applicable to our ideal gas law...