00:01
In this problem solving part 1, so t1 is equal to 80 plus 273 which is equal to 353 kelvin, t2 is equal to 180 plus 273 which is equal to 453 kelvin.
00:19
The value of cv is equal to r by k minus 1, which is equal to 2 .869, multiplication 10 to the power 2 by 1 .4 minus 1.
00:32
Which is equal to 717 jule per k g kelvin i can write u2 minus u1 is equal to c b t2 minus t1 which is equal to 717 multiplication 453 minus 353 which is equal to 71700 jule per kg now solving it further so i can write the the value in part b, h, cp is equal to rk by k minus 1, which is equal to 28, 2 .869, multiplication 10 to the power 2, multiplication 1 .4 by 1 .4 minus 1, which is equal to 1004, joule per kg kelvin.
01:35
The value of h2 minus h1 is equal to cp, t2 minus t1, which is equal to 1004 453 minus 353 which is equal to 100 4 00 u per kg now in part c i can write row 1 is equal to p 1 by r t 1 which is equal to 301 multiplication 10 to the power 3 by 2 .869 multiplication 10 to the power 2 multiplication 353 which is equal to 2 .972 kg per meter cube.
02:18
Now i can write the value of row 2 is equal to p2 by rt1 which is equal to 181 multiplication 10 to the power 3 by 2 .869 multiplication 10 4 .53 which is equal to 1 .3926 kg per meter cube...