00:01
Hi, everybody.
00:02
So for this one, we find the final relative and specific community and volume of v2 over v1.
00:09
Okay.
00:11
So for this, we need to find the pv, which is going to equal to 5 times pg1, which is 0 .8 times 5 .628.
00:31
It's going to be 4 .5024 kilopascals.
00:38
Okay.
00:41
And now we can find the humidity, which is going to be 0 .622 times pv1 over p1 minus pb1, and it's going to be 0 .622 times 4 .502, divided by 100 minus 4 .4.
01:12
And this is going to equal to 0 .02932.
01:20
And so we need to check if state 2 is saturated.
01:24
So to do that, we have your committees are equal to each other.
01:30
And so we have mid -82 is going to be 0 .0.
01:36
So what we're going to do is use this equation.
01:42
I don't feel like rewriting it.
01:45
And since this is equal to each other, and we need to find pv2, we do 0 .02932, okay.
01:55
And it's going to equal 0 .622.
01:59
Okay.
02:00
And we got pv2 divided by 500 minus pv2.
02:08
Okay.
02:10
And so we have 0 .04713 and 500 minus p.
02:20
Oops, it's supposed to be p and out of five.
02:23
P v2 equals pv2.
02:28
Okay, and now we got pv2 is going to equal to 1 .04713 times, oops, there we go.
02:45
Let's just make sure we write everything correctly, 23 .565.
02:52
Okay.
02:54
So then your pv square two is going to be 22 .504.
03:02
Three kilo -pascals.
03:05
Okay.
03:07
And so your pv squared is greater than the pg.
03:12
So the state is saturated.
03:14
So state is saturated.
03:27
And so that means it that five to equals 100 % because it's saturated.
03:37
And so that's good.
03:39
And now we can find the humidity of 2, which is going to be 0 .622 times 5 .628, divided by 500 minus 5 .628.
03:57
And we get 0 .0078.
04:02
08, okay.
04:06
And so we have initial volume...