Question
Air is expanded from 2000 kPa and $500^{\circ} \mathrm{C}$ to $100 \mathrm{kPa}$ and $50^{\circ} \mathrm{C}$. Assuming constant specific heats, determine the change in the specific entropy of air.
Step 1
We do this by adding 273 to the Celsius temperature. So, $T_1 = 500^{\circ}C + 273 = 773K$ and $T_2 = 50^{\circ}C + 273 = 323K$. Show more…
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Air is expanded from 200 psia and $500^{\circ} \mathrm{F}$ to 100 psia and $50^{\circ} \mathrm{F}$. Assuming constant specific heats, determine the change in the specific entropy of air.
Air is expanded from 2000 kPa and 500°C to 100 kPa and 50°C. Assuming constant specific heats, determine the change in the specific entropy of air. [Hint: cp = 1.040 kJ/kg.K & R = 0.287 kJ/kg.K] a. Δsair = 1.0478 kJ/kg.K. b. Δsair = 0.478 kJ/kg.K. c. Δsair = 0.0478 kJ/kg.K. d. Δsair = -0.478 kJ/kg.K. e. Δsair = -0.0478 kJ/kg.K.
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