00:01
They tell us alcohols can act either as weak acids or weak bases, and they want us to show the reaction of methanol with a strong acid, like hydrochloric acid, as well as sodium amid, which is a strong base.
00:18
So in this first case, methanol is going to be acting as a base, since they were telling us that hydrochloric acid is going to be our strong acid, and we should recall that from general chemistry as well.
00:31
So let's go ahead and actually draw how this will react.
00:35
So the only thing with lone pairs and our methanol is going to be that alcohol right there, or the oxygen on the alcohol.
00:43
So what's going to end up happening is, so let me draw this bond going between these.
00:52
One of the lone pairs from the oxygen is going to come over here, still that hydrogen.
00:57
And now this hydrogen doesn't like having the two bonds.
01:00
So it's going to break the bond between the hydrogen and the chlorine, and the bond is going to go to the chlorine here.
01:08
So let's go ahead and actually draw the lone pairs on that chlorine as well.
01:12
So we should end up with, so we have the alcohol, and it's going to have two hydrogens attached to it now.
01:23
One of its lone pairs went to steal that hydrogen, so that means it's going to have one lone pair now.
01:29
And if we were to check out the formal charge for this, it would have a positive charge because it would have 1, 2, 3, 4, 5 electrons in its failance.
01:38
It normally has 6, so it essentially lost one.
01:42
Now for the chlorine, it had 3 loan pairs, so 1, 2, 3.
01:49
It gained one from that bond, so it has 4.
01:52
Now chlorine is going to have 8 electrons.
01:55
It normally has 7, so this is going to have a negative charge.
01:58
All right.
01:59
Now what about when it reacts with sodium amid? so remember, this nitrogen here is going to have two lone pairs on it...