00:01
In this question, we are looking at this molecule called alkylbenzylymethyl ammonium chloride.
00:08
And we are asked to come up with three different sets of reagents, each one containing an alkali chloride and an amine that can be used to synthesize this molecule.
00:18
So basically we're going to take each of the three different groups on the nitrogen and make them into alkyl chlorides and we'll leave the amine behind.
00:29
So first i'm going to take off this long chain here and make that into the alkali chloride.
00:34
So number one, the amine will be, oops, that actually doesn't have an h there.
00:45
This is a tertiary amine here, and then we'll take this chain, which is 1, 2, 3, 4, 5, 6, 7, 8.
00:53
Carbons long, so chlorine, 1, 2, 3, 4, 5, 6, 7, 8.
00:58
This will be our alkyloid.
01:01
So what will happen in this reaction is the lone pair on the amine will come in and attack this carbon and kick off the chlorine and an s &2 reaction to form this product...