00:01
So we have the following reaction, and we want to try to understand why the z isomer is more reactive in an e2 reaction, as opposed to the e -isomer.
00:10
So what we can do here is we can go ahead and draw the corresponding isomers.
00:17
So i'll go ahead and draw the z -isomer first.
00:34
So for the z -isomer, our highest priority groups, right? we have our chloride, and then we also have our...
00:45
Acid here as our highest priority groups so they are zeusamine and they are z for our e isomer we can go and draw that oops sorry it's going to look like this actually okay let me see here our highest priority groups which is the acid and the chloride are now on opposite sides therefore they exhibit the e e -configuration.
01:36
So we want to try to understand, okay, so why is the z isomer going to be more reactive in an e2 elimination reaction as opposed to the e -isomer? well, recall that for an e2 elimination reaction, this generally favors our beta hydrogen and our leaving group, which is our chloride here, to exhibit anti -parriplanar geometry...