00:01
So for this question, we're supposed to compare the percent nitrogen of four different fertilizers.
00:08
And you're supposed to find the one that has the highest mass percentage of nitrogen.
00:12
So the way that we're going to do this is we're going to find how much nitrogen is each fertilizer.
00:17
Divide that by the overall molecular mass, multiply by 100%, and that'll give us the percent nitrogen.
00:23
So the first fertilizer that we have is urea.
00:28
So the first thing we need to do is want to find how much the nitrogen is in here or the mass of the nitrogen.
00:36
Well, we have two nitrogen atoms because it's two distributes.
00:41
So the mass of the nitrogen is just 2 times 14 .01, it's 28 .02.
00:51
So now we need to find the total molecular mass.
00:56
Well, we know that the total molecular mass.
01:00
Mass is going to include two nitrogen atoms.
01:04
We also have four hydrogen atoms because that two also distributes, so we have four times 1 .00.
01:12
And we have a carbon atom and an oxfarin atom.
01:15
And the amus for both of those elements are 12 .01, 16 .00 respectively.
01:25
And plug that into the calculator will get that the total molecular mass is 60 .066.
01:32
Amu.
01:34
So now we just take the mass of the nitrogen, divided by the total molecular mass, multiply by 100, and you guys at the percent nitrogen is 46 .65%.
01:49
So that is the answer to part a.
01:54
Now for part b, for part b, we have ammonium, a nitrate, or nh4, and03.
02:02
So once again, you want to find the mass of the nitrogen.
02:05
We have two nitrogen atoms.
02:07
One here and one there, so it's just two times the amu of nitrogen, which is 14 .01, and that yields 28 .02 atomic mass units of nitrogen.
02:19
Now the total molecular mass.
02:24
Well, like before, it's going to include those two atoms of nitrogen, and we also have four atoms of hydrogen, which is four times 1 .08, and then three oxygens, which is 16 .00.
02:40
And when we multiply all this together, you get that the total molecular mass of the entire compound is 80 .04, amu.
02:54
So we take the mass of the nitrogen, divided by the total molecular mass, multiply by 100, and we get our answer is 35 .2.
03:06
0 % nitrogen.
03:12
Part c...