00:01
Okay, number 42.
00:04
The problem is dinosaur running.
00:07
Oh, interesting.
00:09
An article titled how dinosaurs ram explains that the local motion of different -sized animals can be compared when they have the same front number defined as f equals v squared divided by g multiplied l, where v is the velocity, g is the acceleration of gravity.
00:35
Now it's a constant here, which is 9 .81 m per second square, and l is the length in meters.
00:47
Okay, a1 resort described in the article is that different animals change from a crote to gallop, the same fraud lumber roughly 2 .56.
01:06
Okay, so we have the same fraud lumber, 2 .56.
01:14
Now find the velocity at which this change occurs from a ferret with a lagnance of 0 .09 and a rhinoceros, okay, with a lagoonine, of 1 .2m.
01:35
So we got f equals 2 .56 which is a constant here in this situation f is 2 .56.
01:47
We want to know the v where we have the g is 9 .81 and we have the likeness for those two different animals so we just need plugging for each one.
01:59
Okay, so a, we have f equals v squared divided by g l.
02:08
Now for ferret f is 2 .56, g is 9 .81.
02:23
Ferret.
02:26
His leg means is short, 0 .0 line.
02:32
We plug in, we got 2 .56 equals.
02:37
9 .81, multiply 0 .09, we square.
02:44
Now we in the speed we want to know.
02:51
Now we square equals, okay, let's pull out our calculator.
02:57
Just 2 .56, multiply 9 .81, multiply 0 .09 equals.
03:09
Now we take a square root.
03:11
So we, okay, we square is 2 .26.
03:21
We eat roughly 1 .503 meters per second.
03:31
Okay, now this is the speed for a ferret.
03:35
What about the rhinoceros? the only difference is rhinoceros has a legnines 1 .2 meters, which is way longer.
03:54
And we just plug in that 2 .56, that's the same, equals we, okay, that's called we are, sub r for rhinoceros, 9 .81, multiply 1 .2.
04:13
Now we are equals.
04:17
Okay, 2 .56, multiply 9 .81, multiply 1 .81, multiply 1 .81, multiply 1 .2 .2 .56, multiply 1 .1, multiply 1 .2...