00:01
The first part of this question is looking for the actual names of the reactants and the products.
00:05
So the reaction that we have is co, are reacting with hno3 to produce co, n -o -3, 2 and n -2 and h -2o.
00:24
So we've got the solid, here we've got a concentrate, and here we've got the n -o2 and the rest of the products.
00:35
So looking at this, this is going to be copper and here we've got nitric acid.
00:43
Then this is copper nitrate, commonly, so called copper 2 nitrate.
00:51
And here we've got nitrogen, nitrogen dioxide, and here we've got our water which is liquid h2o.
01:00
Then moving on to the next part, we've been asked for the balanced chemical equation for the reaction of copper with nitric acid.
01:07
So we've got cu reacting with hno3 to produce cuno3 2 plus no2 and h2o.
01:20
Now the balancing of this chemical reaction, we need to have the same number of atoms of each elements in the left hand side and the right hand side.
01:29
So for that we need 4 moles of the nitric acid, 2 moles of the nitrogen dioxide and 2 moles of the h2o.
01:38
Then moving on to part c, if we look at the oxidation numbers, here we've got the oxidation number of copper be equal to zero.
01:49
The oxidation number of hydrogen in nitric acid, it is positive 1, that of nitrogen it is positive 5, and that of oxygen it is negative 3...