00:01
So for this problem, we want to write out the chemical equation for the reaction between xenon and fluorine to form xenon tetrafluoride.
00:09
Let's begin by writing out our reactants and products.
00:12
So for our reactants, we have xenon and fluorine.
00:18
And remember, when the halogens are in gaseous form or in their natural state, they are diatomic, meaning there are two of the same atoms in the compound.
00:26
So there are two fluorine atoms, and our product is xenon tetrafluoride.
00:30
Now remember your latin roots, tetra is latin for four.
00:34
So there are four fluorine atoms.
00:37
And there is no latin root affixed to xenon, so we assume it's mono.
00:41
So there's only one xenon atom attached...