Aluminum reacts with oxygen to give aluminum oxide.
$$
4 \mathrm{Al}(\mathrm{s})+3 \mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{Al}_{2} \mathrm{O}_{3}(\mathrm{s})
$$
What amount of $\mathrm{O}_{2},$ in moles, is needed for complete reaction with 6.0 mol of Al? What mass of $\mathrm{Al}_{2} \mathrm{O}_{3},$ in grams, can be produced?