Question
Aluminum reacts with oxygen to yield aluminum oxide. If 5.0 $\mathrm{g}$ of Al reacts with 4.45 $\mathrm{g}$ of $\mathrm{O}_{2},$ what is the empirical formula of aluminum oxide?
Step 1
For aluminum, we divide the given mass by its molar mass. \[ \frac{5.0 \, \text{g}}{26.98 \, \text{g/mol}} = 0.185 \, \text{moles of Al} \] Show more…
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