00:01
For part a, we're going to note that the normal force is equaling mg.
00:04
And here, the maximum static frictional force, say lowercase f, is going to be equalling to the coefficient of static friction mg.
00:16
And so this would be equalling to 0 .52, multiplied by 11 kilograms, multiplied by 9 .8 meters per second squared.
00:27
And this is giving us 56 neutrons.
00:29
Therefore, in order to start moving, the horizontal force f must have a magnitude that is just a bit above 56 newton.
00:41
Because 56 newton's is a minimum.
00:44
So this will be your answer for part a, for part b.
00:47
We know that we're going to apply newton's second law in the y direction.
00:50
So f sine of theta plus the normal force is going to be equaling to mg...