Question
An $18.0-\mathrm{kg}$ box is released on a $37.0^{\circ}$ incline and acceleratesdown the incline at 0.220 $\mathrm{m} / \mathrm{s}^{2} .$ Find the friction forceimpeding its motion. How large is the coefficient of friction?
Step 1
The parallel component is given by $mg \sin(\theta)$ and the perpendicular component is given by $mg \cos(\theta)$, where $m$ is the mass of the box, $g$ is the acceleration due to gravity, and $\theta$ is the angle of the incline. Show more…
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(II) An $18.0-\mathrm{kg}$ box is released on a $37.0^{\circ}$ incline and accelerates down the incline at 0.270 $\mathrm{m} / \mathrm{s}^{2}$ . Find the friction force impeding its motion. How large is the coefficient of kinetic friction?
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(II) A $25.0-\mathrm{kg}$ box is released on a $27^{\circ}$ incline and accelerates down the incline at 0.30 $\mathrm{m} / \mathrm{s}^{2}$ . Find the friction force impeding its motion. What is the coefficient of kinetic friction?
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