00:01
So here, we know that in coming to equilibrium, the heat lost by the 100 cubic centimeters of liquid water is absorbed by the mass.
00:11
So we can say that the change in heat transfer would equal zero because we're going to say that because it is in a thermos, there isn't going to be any heat transfer between the system and its environment.
00:27
So we can say that the heat transfer from the warm water cooling plus the heat transfer from the ice warming or rather ice warms to zero degrees celsius plus the heat needed for the ice to melt plus the heat needed for the melted ice to warm.
01:05
This is all equaling zero.
01:09
So we can say that the specific heat of water times the mass of the water times temperature final minus 20 degrees plus mass of the ice specific heat of the ice times zero degrees minus negative 10 degrees plus the latent heat of formation for water times the mass of the ice plus the mass of the water times the specific heat.
01:38
Sorry, the mass of the ice times the specific heat of the water times temperature final minus zero degrees celsius.
01:50
This is equaling zero.
01:52
And essentially we're trying to find the final temperature.
01:56
We know that here the specific heat, the latent heat of formation is equaling 330 ,000 joules per kilogram and we can then solve at this point, also knowing that the specific heat of water is equaling 4 ,190 joules per kilogram per kelvin, we can then say that the final temperature is going to be equal to approximately 12 .24 degrees celsius.
02:42
Now, this is going to be equivalent to essentially 285 .39 kelvin, and this is simply adding 273 .15 kelvin to the temperature in celsius in order to convert to kelvin.
03:01
So converting to kelvin from celsius is simply adding 273 .15.
03:09
We can then use a sample problem 20 .01...