An 8.00-kg box sits on a ramp that is inclined at 33.0^∘above the horizontal. The coefficient of

Name: Problem 73, Chapter 5: University Physics with Modern Physics
Uploaded: 2023-09-13T18:11:06-08:00
Duration: 2 min 13 s
Channel: Nicholas Mogoi
Description: An 8.00-kg box sits on a ramp that is inclined at 33.0^∘above the horizontal. The coefficient of kinetic friction between the box and the surface of the ramp is = 0.300. A constant horizontal force F = 26.0 N is applied to the box (Fig. P5.73), and the box moves down the ramp. If the box is initially at rest, what is its speed 2.00 s after the force is applied? Figure e5.73(Figure Cant copy)

step 1 So consider the mass of this box is 8 .0 kilogram and theta is 33 degrees and then our coefficie

Question

An 8.00-kg box sits on a ramp that is inclined at 33.0$^\circ$ above the horizontal. The coefficient of kinetic friction between the box and the surface of the ramp is $\mu_k =$ 0.300. A constant $horizontal$ force $F =$ 26.0 N is applied to the box ($\textbf{Fig. P5.73}$), and the box moves down the ramp. If the box is initially at rest, what is its speed 2.00 s after the force is applied? Figure e5.73(Figure Cant copy)

   An 8.00-kg box sits on a ramp that is inclined at 33.0$^\circ$ above the horizontal. The coefficient
of kinetic friction between the box and the surface of the ramp is $\mu_k =$ 0.300. A constant $horizontal$ force $F =$ 26.0 N is applied to the box ($\textbf{Fig. P5.73}$), and the box moves down the ramp. If the box is initially at rest, what is its speed 2.00 s after the force is applied? Figure e5.73(Figure Cant copy)

University Physics with Modern Physics

Hugh D. Young 14th Edition

Chapter 5, Problem 73

Instant Answer

Solved by Expert Nicholas Mogoi

09/13/2023

Step 1

The net force acting on the box is the sum of the gravitational force acting down the ramp, the applied force, and the frictional force. This net force is equal to the mass of the box times its acceleration. We can write this as: \[Mg \sin \theta + F \cos \theta - Show more…

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An 8.00-kg box sits on a ramp that is inclined at 33.0$^\circ$ above the horizontal. The coefficient of kinetic friction between the box and the surface of the ramp is $\mu_k =$ 0.300. A constant $horizontal$ force $F =$ 26.0 N is applied to the box ($\textbf{Fig. P5.73}$), and the box moves down the ramp. If the box is initially at rest, what is its speed 2.00 s after the force is applied? Figure e5.73(Figure Cant copy)