Question
An 83 kg man eats a banana of energy content $418 \mathrm{kJ}(100 \mathrm{kcal}) .$ If all of the energy from the banana is converted into kinetic energy of the man, how fast is he moving, assuming he starts from rest?
Step 1
The formula for kinetic energy is given by: \[ KE = \frac{1}{2} m v^2 \] where \( m \) is the mass of the man and \( v \) is the velocity of the man. Show more…
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