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An advertisement claims that a particular automobile can "stop on a dime." What net force would actually be necessary to stop a 850 -kg automobile traveling initially at 45.0 $\mathrm{km} / \mathrm{h}$ in a distance equal to the diameter of a dime, which is 1.8 $\mathrm{cm} ?$

$3.7 \times 10^{6} \mathrm{N}$

Physics 101 Mechanics

Chapter 4

Newton's Laws of Motion

Physics Basics

Motion Along a Straight Line

Motion in 2d or 3d

University of Michigan - Ann Arbor

Simon Fraser University

Hope College

McMaster University

Lectures

03:28

Newton's Laws of Motion are three physical laws that, laid the foundation for classical mechanics. They describe the relationship between a body and the forces acting upon it, and its motion in response to those forces. These three laws have been expressed in several ways, over nearly three centuries, and can be summarised as follows: In his 1687 "Philosophiæ Naturalis Principia Mathematica" ("Mathematical Principles of Natural Philosophy"), Isaac Newton set out three laws of motion. The first law defines the force F, the second law defines the mass m, and the third law defines the acceleration a. The first law states that if the net force acting upon a body is zero, its velocity will not change; the second law states that the acceleration of a body is proportional to the net force acting upon it, and the third law states that for every action there is an equal and opposite reaction.

04:16

In mathematics, a proof is a sequence of statements given to explain how a conclusion is derived from premises known or assumed to be true. The proof attempts to demonstrate that the conclusion is a logical consequence of the premises, and is one of the most important goals of mathematics.

03:31

An advertisement claims th…

03:44

03:02

02:02

09:47

05:04

Can cars "stop on a d…

03:12

(II) Can cars "stop o…

03:43

03:52

What average force is requ…

03:14

(a) What force is required…

02:30

A 1580-kg car is traveling…

08:13

02:53

01:53

(II) What average force is…

02:23

ssm mmh A 1580-kg car is t…

01:31

01:45

(a) Find an equation to de…

but in this problem, training for what? The force necessary to make this car stop on a dime. So here's my equation involving salvation. Basti. Um and here's my diagram. My cute Hey, grab with the problem. So let's just put some stuff in and see what happens, you know? So I have the X. That's the final bill. Austria. We want our final velocity to be zero minus. Um, we need to change this $45 per hour. Well, that's 45 1000 meters. Divided by 3600. It's me to to 4500 1000 divided by 3600 12.5, 12.5 years per second. So 12.5 squared equal to to a X. Now the final distance will be 1.8 centimeters. What you were doing, everything in meters will need to do 1.8 centimeters. This distance is equal to, um see, that is equal to If I want to make that a meter, I would divide by 100. Yeah, because one 100 centimeters goes into one meters right by hundreds, I get point 018 meters. It's a 0.18 and then our initial distance, we would say a zero and we'll end up with year as I have Negative 156.25 equal to two times 18 is 36. So 360.0 36 times acceleration of X, which means that the acceleration of X is equal to divided by 0.0 36 4000 340 points. Three and negative. Which makes sense because our exploration should be a de acceleration for stopping card. So we would be wanting a force in the left direction. Okay, so the acceleration, I believe the question was, What's the initial the force necessary? Well, that's acceleration that we needed. And then what would it be? The succession replied to would be applied to the mass of the card so the force needed to stop is equal to the mass of the car. Times The acceleration negative for 3 40.3 meters per second squared, resulting in a grand total of for 30 0.3 times 850 three million. 6892553 16 95. Nunes taking the negative because they read Newton's another direction. But the magnitude of poster of all is a force of 36 3,609,205 Nunes, which is a cruel Raisi large amount.

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