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An aeroplane leaves an airport and flies due north at a speed of $1000 \mathrm{~km}$ per hour. At the same time, another aeroplane leaves the same airport and flies due west at a speed of $1200 \mathrm{~km}$ per hour. How far apart will be the two planes after $1 \frac{1}{1}$ hours?
Geometry
Chapter 6
Triangles
Section 5
Areas of Similar Triangles
Similarity
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No, This is followed # 11. Uh, and this, we have two airplanes that live first lives, Uh, do not at a speed of 1,024 hours at the same time. Another airplane. Okay, so let us suppose this is not south. A stent fist. Okay. First had a plan, flies do not at a speed of 1000 kilometer border. We have to find everything after 11 by two hours, so 1.5 hours The distance the event. Bye airplane, one and 1/2 hours will be equal to spare into time. It is 1002 time in three x 2. So 1500 km. Similarly distance traveled. Bye. It will plan to In the same time will be 1200 into three x 2 That is 1800 kilometers. Okay. Now only this draw the pictorial representation. Okay, so first off the plane is leaving. Do not from here. This is the airport airport, it has just from all it has come to A and this distance is 1500 km 1500 kilometers second do you invest? And this has come here and it is supposed to be and 1800 kilometers. So we need to find the distance between there. I understand it in them, but definitely we'll be using by the worst term. So A B will be equal to oh, a square place or be square under the square root. Oh, a square 1500 square bless 18. Every square. Okay, so 100 will definitely be taken out and 15 to 15. 18 to 18, uh, 324. So 100 in two, 500 49 key, So this is 500 and 49. So what we're doing is mm Yes, mine. So 549, we'll be writing it has 549 and two 16, 19- 61. The required distance maybe is things will be taken out, Stay in there and there were 16 kilometers. Thank you.
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