Question
An air column in a pipe which is closed at one end will be in resonance with a vibrating tuning fork of frequency $264 \mathrm{~Hz}$ if the length of the air column in $\mathrm{cm}$ is:(Speed of sound in air $=340 \mathrm{~m} / \mathrm{s}$ )(a) $32.19 \mathrm{~cm}$(b) $64.39 \mathrm{~cm}$(c) $100 \mathrm{~cm}$(d) $140 \mathrm{~cm}$
Step 1
Step 1: The fundamental frequency of a pipe closed at one end is given by the formula: \[f = \frac{v}{4L}\] where \(f\) is the frequency, \(v\) is the speed of sound, and \(L\) is the length of the pipe. Show more…
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An air column in a pipe, which is closed at one end will be in resonance with a vibrating tuning fork of frequency $264 \mathrm{~Hz}$, What is the length of the column if it is in $\mathrm{cm} ?$ (speed of sound in $\operatorname{air}=330 \mathrm{~m} / \mathrm{s}$ ) (A) $62.50$ (B) $15.62$ (C) 125 (D) $93.75$
An air column in a pipe, which is closed at one end, is in resonance with a vibrating tuning fork of frequency $264 \mathrm{~Hz}$. If $v=330 \mathrm{~ms}^{-1}$, the length of the column in $\mathrm{cm}$ is (a) $31.25$ (b) $62.50$ (c) $93.75$ (d) 125
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Round 2
A resonating air column shows resonance with a tuning fork of frequency $256 \mathrm{~Hz}$ at column lengths $33.4 \mathrm{~cm}$ and $1018 \mathrm{~cm}$. The speed of sound in air is (a) $300 \mathrm{~m} \mathrm{~s}^{-1}$ (b) $250 \mathrm{~ms}$ (c) $390 \mathrm{~m} \mathrm{~s}^{-1}$ (d) $350 \mathrm{~ms}$
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