Question
An air-core solenoid with 68 turns is 8.00 cm long and has a diameter of 1.20 cm. When the solenoid carries a current of 0.770 A, how much energy is stored in its magnetic field?
Step 1
Step 1: The magnetic field B in a solenoid is given by the formula: \[B = \mu_{0} n I\] where \(\mu_{0}\) is the permeability of free space, \(n\) is the number of turns per unit length, and \(I\) is the current. Show more…
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An air-core solenoid with 68 turns is $8.00 \mathrm{~cm}$ long and has a diameter of $1.20 \mathrm{~cm} .$ How much energy is stored in its magnetic field when it carries a current of $0.770 \mathrm{~A}$ ?
(I) The magnetic field inside an air-filled solenoid $38.0 \mathrm{~cm}$ long and $2.10 \mathrm{~cm}$ in diameter is $0.600 \mathrm{~T}$. Approximately how much energy is stored in this field?
(I) The magnetic field inside an air-filled solenoid 36 $\mathrm{cm}$ long and 2.0 $\mathrm{cm}$ in diameter is 0.80 $\mathrm{T}$ . Approximately how much energy is stored in this field?
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