Question
An air-pipe friction experiment consists of a smooth brass tube with $63.5 \mathrm{mm}$ inside diameter, the distance between pressure taps is $1.52 \mathrm{m}$. The pressure drop is indicated by a manometer filled with Meriam red oil. The centerline velocity $U$ is measured with a pitot cylinder. At one flow condition, $U=23.1 \mathrm{m} / \mathrm{s}$ and the pressure drop is $12.3 \mathrm{mm}$ of oil. For this condition, evaluate the Reynolds number based on average flow velocity. Calculate the friction factor and compare with the value obtained from Eq. 8.37 (use $n=7$ in the power-law velocity profile).
Step 1
From equation 8.20, with $n=7$, we have $U_{avg} = \frac{2n}{n+1}U = \frac{2*7}{7+1}U = 0.875U$. Substituting the given value of $U$, we get $U_{avg} = 0.875*23.1 = 20.2125 \, \mathrm{m/s}$. Show more…
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