00:02
So here for part a, we can find the phase constant.
00:04
We know that the initial position is equaling the amplitude multiplied by cosine of the phase constant.
00:13
We can say that the initial velocity in the x direction would be equaling to negative omega a sine of finite.
00:24
Dividing the first equation by the second equation, we get the sine sine of phi not divided by cosine.
00:34
A finite equalling tangent of phi not equaling negative velocity initial in the x divided by omega initial x and so we can find this would be equaling to arc tan of negative 36 .3 centimeters per second divided by 2 pi over the period so we can say 2 pi over the period so we can say 2 over 1 .5 seconds and then this would be multiplied by negative 5 .00 centimeters and we find that this is giving us we have pi over three radians or negative 2 over 3 pi radians now the tangent function repeats every 180 degrees so we can so there are always two possible values when evaluating the arc tan function.
01:47
That's why we're getting two different answers.
01:49
Now, here we have an object with a negative position, but it's moving to the right, which means that here, it will be in the third quadrant.
02:01
And so we can say that if we're in the third quadrant, of the third quadrant of the corresponding circular motion...