Question
An air-track glider is attached to a spring. The glider is pulled to the right and released from rest at $t=0$ s. It then oscillates with a period of $2.0 \mathrm{s}$ and a maximum speed of $40 \mathrm{cm} / \mathrm{s}$a. What is the amplitude of the oscillation?b. What is the glider's position at $t=0.25 \mathrm{s} ?$
Step 1
The angular frequency is equal to $2\pi$ divided by the period. So, we have: \[ \omega = \frac{2\pi}{T} = \frac{2\pi}{2.0 \, \text{s}} = \pi \, \text{rad/s} \] Show more…
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An air-track glider is attached to a spring. The glider is pulled to the right and released from rest at $t=0$ s. It then oscillates with a period of $2.0 \mathrm{s}$ and a maximum speed of $40 \mathrm{cm} / \mathrm{s}$. a. What is the amplitude of the oscillation? b. What is the glider's position at $t=0.25 \mathrm{s} ?$
An air-track glider is attached to a spring. The glider is pulled to the right and released from rest at t=0 s. It then oscillates with a period of 2.0 s and a maximum speed of 40 cm/s. What is the amplitude of the oscillation? What is the glider’s position at t=0.25 s?
III An air-track glider is attached to a spring. The glider is pulled to the right and released from rest at $t=0$ s. It then oscillates with a period of $2.0 \mathrm{s}$ and a maximum speed of $40 \mathrm{cm} / \mathrm{s}$. a. What is the amplitude of the oscillation? b. What is the glider's position at $t=0.25 \mathrm{s} ?$
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