Question
An alpha particle (charge $=+2.0 e$ ) is sent at high speed toward a gold nucleus (charge $=+79 e$ ). What is the clectric force acting on the alpha particle when the alpha particle is $2.0 \times 10^{-14} \mathrm{m}$ from the gold nucleus? (See Sample Problem 17A.)
Step 1
The charge of the alpha particle is \( q_1 = +2.0e \) and the charge of the gold nucleus is \( q_2 = +79e \), where \( e \) is the elementary charge (\( e = 1.6 \times 10^{-19} \, \text{C} \)). Show more…
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An alpha particle (charge $=+2.0 e$ ) is sent at high speed toward a gold nucleus (charge $=+79 e$ ). What is the electric force acting on the alpha particle when the alpha particle is $2.0 \times 10^{-14} \mathrm{m}$ from the gold nucleus?
A gold nucleus has a radius of $7.3 \times 10^{-15} \mathrm{m}$ and a charge of $+79 e .$ Through what voltage must an $\alpha$ -particle, with its charge of $+2 e,$ be accelerated so that it has just enough energy to reach a distance of $2.0 \times 10^{-14} \mathrm{m}$ from the surface of a gold nucleus? (Assume the gold nucleus remains stationary and can be treated as a point charge.)
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