00:01
So here we have the thermal energy lost by the aluminum block, equaling the mass of the aluminum times the specific heat capacity of aluminum, multiplied by the equilibrium temperature minus the initial temperature of the aluminum.
00:21
For the heat gained by the water, this would be equal to the mass of the water times the specific heat of the water, multiplied by the equilibrium temperature minus the initial temperature of the water.
00:32
We can say that the heat lost by the aluminum plus the heat gained by the water should equal zero.
00:46
And so we can then say that the mass of the aluminum, specific heat of the aluminum, t minus the initial temperature of the aluminum plus the mass of the water times the specific heat of the water, multiplied by the equilibrium temperature minus the initial temperature of the water equaling zero.
01:13
And we can actually solve for the, we can essentially solve for the temperature t, the equilibrium temperature.
01:23
This would be equalling to the mass of the aluminum times the specific heat of the aluminum times the initial temperature of the aluminum plus mass of the water, specific heat of the water, initial temperature of the water, and this would be divided then by the mass of the aluminum times the specific heat of the aluminum plus the mass of the water times the specific heat of the water...