00:01
So we have the number of visible horizontal lines in the ntsc tv is n equals 485.
00:08
Let's say h is the height of the tv.
00:11
Then the spacing between the lines in the tv would be d equals h over n, which is going to be h over 485.
00:22
Now, when the screen is viewed from a distance of r, let's say r is distance, between the screen and the observer.
00:44
All right? so this is the distance between the screen and the observer.
00:51
Then the angular separation between the two lines, those two horizontal lines would be theta equals d over r.
01:02
All right.
01:03
And if the lines are to be unresolved, then theta must be less than the minimum angle of resolution required by the raleigh criterion.
01:12
So what that means is theta has to be less than theta mean that is required by the criterion to be able to resolve something else.
01:27
So this actually means d over r has to be less than 1 .22 lambda over d.
01:38
Here, lambda is the wavelength of the light being used.
01:41
D is the aperture diameter.
01:45
And in this case, the aperture diameter is 5mm.
01:51
It is given...