Question
An amplifier has a voltage gain of 65 and a $25-\mathrm{k} \Omega$ load (output) resistance. What is the peak output current through the load resistor if the input voltage is an ac signal with a peak of $0.080 \mathrm{~V} ?$
Step 1
The output voltage is the gain times the input voltage. In this case, the gain is 65 and the input voltage is 0.080 V. So, the output voltage is $65 \times 0.080 \, V = 5.2 \, V$. Show more…
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(II) An amplifier has a voltage gain of 75 and a 25-k$\Omega$ load (output) resistance. What is the peak output current through the load resistor if the input voltage is an ac signal with a peak of 0.080 V?
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An amplifier has a short-circuit current gain of $10 .$ When operated with a $50 . \Omega$ load, the current gain is $8 .$ Find the output resistance of the amplifier.
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