Question

An aniline-alcohol solution is flowing at a velocity of $10 \mathrm{fps}$ through a long, 1 -in.-ID thin-wall tube. Steam is condensing at atmospheric pressure on the outer surface of the tube, and the tube wall temperature is $212^{\circ} \mathrm{F}$. The tube is clean, and there is no thermal resistance from scale deposits on the inner surface. Using the physical properties tabulated below, estimate the heat transfer coefficient between the fluid and the pipe using Eqs. $(6.60)$ and (6.61) and compare the results. Assume that the bulk temperature of the aniline solution is $68^{\circ} \mathrm{F}$, and neglect entrance effects. $$ \begin{array}{|c|c|c|c|c|} \hline \begin{array}{l} \text { Temp- } \\ \text { erature } \\ \left({ }^{\circ} \mathrm{F}\right) \end{array} & \begin{array}{l} \text { Viscosity } \\ \text { (centipoise) } \end{array} & \begin{array}{c} \text { Thermal } \\ \text { Conductivity } \\ \left(B t u / \mathrm{h} \mathrm{ft}^{\circ} \mathrm{F}\right) \end{array} & \begin{array}{l} \text { Specific } \\ \text { Gravity } \end{array} & \begin{array}{c} \text { Specific } \\ \text { Heat } \\ \left(B+\mathrm{Bb}^{\circ} \mathrm{F}\right) \end{array} \\ \hline 68 & 5.1 & 0.100 & 1.03 & 0.50 \\ \hline 140 & 1.4 & 0.098 & 0.98 & 0.53 \\ \hline 212 & 0.6 & 0.095 & & 0.56 \\ \hline \end{array} $$

   An aniline-alcohol solution is flowing at a velocity of $10 \mathrm{fps}$ through a long, 1 -in.-ID thin-wall tube. Steam is condensing at atmospheric pressure on the outer surface of the tube, and the tube wall temperature is $212^{\circ} \mathrm{F}$. The tube is clean, and there is no thermal resistance from scale deposits on the inner surface. Using the physical properties tabulated below, estimate the heat transfer coefficient between the fluid and the pipe using Eqs. $(6.60)$ and (6.61) and compare the results. Assume that the bulk temperature of the aniline solution is $68^{\circ} \mathrm{F}$, and neglect entrance effects.
$$
\begin{array}{|c|c|c|c|c|}
\hline \begin{array}{l}
\text { Temp- } \\
\text { erature } \\
\left({ }^{\circ} \mathrm{F}\right)
\end{array} & \begin{array}{l}
\text { Viscosity } \\
\text { (centipoise) }
\end{array} & \begin{array}{c}
\text { Thermal } \\
\text { Conductivity } \\
\left(B t u / \mathrm{h} \mathrm{ft}^{\circ} \mathrm{F}\right)
\end{array} & \begin{array}{l}
\text { Specific } \\
\text { Gravity }
\end{array} & \begin{array}{c}
\text { Specific } \\
\text { Heat } \\
\left(B+\mathrm{Bb}^{\circ} \mathrm{F}\right)
\end{array} \\
\hline 68 & 5.1 & 0.100 & 1.03 & 0.50 \\
\hline 140 & 1.4 & 0.098 & 0.98 & 0.53 \\
\hline 212 & 0.6 & 0.095 & & 0.56 \\
\hline
\end{array}
$$
Show more…
Principles of Heat Transfer
Principles of Heat Transfer
Frank Kreith, Raj M.… 7th Edition
Chapter 6, Problem 20 ↓

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Step 1

** - Velocity of the aniline-alcohol solution, \( V = 10 \, \text{fps} \) - Inner diameter of the tube, \( D = 1 \, \text{in} = \frac{1}{12} \, \text{ft} \) - Bulk temperature of the aniline solution, \( T_b = 68^{\circ} \text{F} \) - Wall temperature of  Show more…

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An aniline-alcohol solution is flowing at a velocity of $10 \mathrm{fps}$ through a long, 1 -in.-ID thin-wall tube. Steam is condensing at atmospheric pressure on the outer surface of the tube, and the tube wall temperature is $212^{\circ} \mathrm{F}$. The tube is clean, and there is no thermal resistance from scale deposits on the inner surface. Using the physical properties tabulated below, estimate the heat transfer coefficient between the fluid and the pipe using Eqs. $(6.60)$ and (6.61) and compare the results. Assume that the bulk temperature of the aniline solution is $68^{\circ} \mathrm{F}$, and neglect entrance effects. $$ \begin{array}{|c|c|c|c|c|} \hline \begin{array}{l} \text { Temp- } \\ \text { erature } \\ \left({ }^{\circ} \mathrm{F}\right) \end{array} & \begin{array}{l} \text { Viscosity } \\ \text { (centipoise) } \end{array} & \begin{array}{c} \text { Thermal } \\ \text { Conductivity } \\ \left(B t u / \mathrm{h} \mathrm{ft}^{\circ} \mathrm{F}\right) \end{array} & \begin{array}{l} \text { Specific } \\ \text { Gravity } \end{array} & \begin{array}{c} \text { Specific } \\ \text { Heat } \\ \left(B+\mathrm{Bb}^{\circ} \mathrm{F}\right) \end{array} \\ \hline 68 & 5.1 & 0.100 & 1.03 & 0.50 \\ \hline 140 & 1.4 & 0.098 & 0.98 & 0.53 \\ \hline 212 & 0.6 & 0.095 & & 0.56 \\ \hline \end{array} $$
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