00:01
Here we have the problem 98.
00:02
In this question, we're going to calculate the concentration of calcium chloride in mass percent.
00:09
So at 50 degree, the pure water has a vapor pressure equal to 92 .6.
00:25
And the calcium chloride solution has a vapor pressure equal to 81 .6.
00:37
So now we need to calculate the mole fraction of the solvent water, from the following equation p solution is equal to more fraction of the solvent times p zero of the solvent p solution is the vapor pressure of the solution and p zero solution solvent is the vapor pressure of the pure water so rearrange the equation and find the more fraction of the solvent is equal to p solution divided by p0 of the solvent.
01:31
This is equal to 81 .6 divided by 92 .6.
01:43
And this will give us equal to 0 .881.
01:48
So this is the more fraction of the solvent.
01:51
So we know that the more fraction of solvent, we can calculate the more fraction of the solvent.
01:57
Is equal to 1 minus the mole fraction of the solvent, 1 minus 0 .881 is equal to 0 .119.
02:13
So assume a sample of 100 moles of solution.
02:29
The calcium chloride dissociate completely given one mole of calcium ion and 2 modes of chloride ion.
02:36
So the value of vanhoff factor is equal to 3.
02:47
So the mole fraction of chloride would be one -third of that of the solute.
02:55
So the moles of solute is equal to one -third times 0 .119 times 100 moles.
03:13
This is equal to 3 .97 moles.
03:19
And the moles of solvent will be 100...