Question
An aqueous solution buffered by benzoic acid $\left(\mathrm{C}_{6} \mathrm{H}_{5}\right.$$\mathrm{COOH}$ ) and sodium benzoate $\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOHNa}\right)$ is0.0500 $\mathrm{M}$ in both compounds. Given that benzoic acid's$K_{\mathrm{a}}$ equals $6.4 \times 10^{-5},$ what is the pH of the solution?
Step 1
The equation is given by: \[pH = pKa + log\left(\frac{[A^-]}{[HA]}\right)\] where \(pKa = -log(Ka)\), \([A^-]\) is the concentration of the base (sodium benzoate), and \([HA]\) is the concentration of the acid (benzoic acid). Show more…
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