00:01
First we recognize that the protonated form of the base, which i'll represent as bh +, reacts with water making the weak base and hydronium ion.
00:12
The ka for the weak acid, the protonated form of the base, is it will be equal to the concentration of the base formed multiplied by the concentration of hydronium ion divided by the concentration of the protonated form of the base.
00:33
The ka value can be determined by taking kw and dividing it by the kb value for aniline, c6, h5, and h2, and this gives us 2 .5 times 10 to the negative 5.
00:48
The hydronium concentration can be determined from the ph.
00:52
It's simply 10 to the negative ph.
00:55
Then we take these two values, we plug them into the ka expression along with the protonated form.
01:08
We plug these two and we calculate the protonated form.
01:14
So i've rearranged the equation.
01:17
They gave us the concentration of the base, it's 0 .50 molar.
01:22
A hydronium concentration we just determined.
01:26
We then divide by the ka value and we get a concentration for the protonated form of 1 .26 molar...