Question

An aqueous solution of a $0.10 M$ monoprotic acid HA has an osmotic pressure of 3.22 atm at $25^{\circ} \mathrm{C}$. What is the percent ionization of the acid at this concentration?

   An aqueous solution of a $0.10 M$ monoprotic acid HA has an osmotic pressure of 3.22 atm at $25^{\circ} \mathrm{C}$. What is the percent ionization of the acid at this concentration?
 
Chemistry
Chemistry
Raymond Chang, Jason… 14th Edition
Chapter 12, Problem 89 ↓
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An aqueous solution of a $0.10 M$ monoprotic acid HA has an osmotic pressure of 3.22 atm at $25^{\circ} \mathrm{C}$. What is the percent ionization of the acid at this concentration?
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Transcript

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00:01 So we have an acid, h -a, and it goes through ionization when it's dissolved in water.
00:11 So you can form h -plus and a -minus.
00:16 And we can verify the extent of this dissociation by examining the van h -hauf factor.
00:25 So we have an experiment for osmotic pressure.
00:29 Using that experiment, we can compute the vennhoff factor, and then we can connect that to the dissociation.
00:37 First, let's think about this dissociation.
00:41 If nothing dissociates, it means that for each h .a.
00:48 That we put in the solution, we just produce one particle.
00:52 Remember? so that means that the vennhoff factor will be one.
00:55 So it means that for each h .a, you produce one particle because it doesn't dissociate, right? now, let's say that everything dissociates.
01:10 So it's a complete dissociation, very strong acid.
01:14 In that case, for each h -a, you produce 1 h -plus and 1 -a -minus.
01:21 So the number of particles is the double...
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