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##### Andy C.

University of Michigan - Ann Arbor

##### Marshall S.

University of Washington

##### Jared E.

University of Winnipeg

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### Video Transcript

for the exposition, we could say that displacement in the X on the extraction would be equaling velocity ex initial times t Because there isn't any. There isn't any acceleration in the ex direction. So this would be 300 meters per second multiplied by co signed 55 degrees multiplied by 40 2.0 seconds. This is equaling essentially 700 7000. Rather 200 7000 220 seven meters for Delta. Why, this would be equally the y initial T plus 1/2 g t squared. We're gonna choose positive. We're gonna choose upwards to be positive. And so delta Y is equaling 300 meters per second sign of 55 degrees times 42.0 seconds plus 1/2 times negative, 9.80 meters per second squared times 42.0 seconds. Quantity squared and we find that delta Y is equaling here. It would be 1678 meters, so this would be your position. Your final positions for your final coordinates would be 7227 meters comma 1678 meters. This would be your final position in your final answer. That is the end of the solution. Thank you for watching.

Carnegie Mellon University
##### Andy C.

University of Michigan - Ann Arbor

##### Marshall S.

University of Washington

##### Jared E.

University of Winnipeg

Lectures

Join Bootcamp