00:03
In this problem, we have an astronaut and his twin.
00:07
The astronaut takes off into space, traveling basically just under eight kilometers per second.
00:13
For a certain amount of time, he comes back.
00:16
And when they compare clocks, the twin and the astronaut, compare clocks, they find that the clock that stayed with the twin on earth reads one second more than the clock on the spaceship that's to travel with the astronaut.
00:32
So that says that the twin that stayed behind is one.
00:34
Second older than the twin that left.
00:38
Now let's talk about which one is proper time, which one is dilated time.
00:43
Topper time, the two -adventure timing must take place to the same position so you can use a single clock.
00:49
The astronaut is sitting here at his origin.
00:53
Remember in his frame, his frame, he's at rest.
00:56
He experiences the spaceport where he takes off.
00:58
Whatever amount of time later he comes back to that same spaceport still at his origin.
01:05
So he experienced that's a space port.
01:06
He experienced that.
01:06
Space port at his origin, same position.
01:10
So he could use a single clock.
01:12
So he gives the astronaut frame, clock in that frame gives proper time.
01:18
The earth then gives dilated time.
01:26
Now, let me define just another quantity here just to just to make it simple algebraically, just delta.
01:34
There's no, no physical meaning.
01:36
Just i don't want to be carrying around the, the, the, the, the, the, the, the, the, um, subscripts here because it may confuse the situation in a second.
01:46
And i'll show you what i mean by that in a second.
01:48
So let's now do our time violation formula.
01:52
So we have delta t's gamma, delta t not, which in this case means delta t sub e is equal to gamma, delta t sub a, which is the same as delta t sub a over square root 1 minus v squared over c square.
02:19
We're going to need that in a second.
02:23
Now, you say, well, isn't this two equations and two unknowns? can't we just substitute for delta t .e, put it in terms of delta t .a.
02:38
Then solve for our time.
02:45
Certainly, you could do that.
02:48
One problem.
02:50
This number, look at this.
02:53
It's only eight kilometers per second.
02:55
Basically, eight times 10 to the three meters per second, compared to three times 10 to the eight.
03:00
There's a 10 to the fifth power difference between the two.
03:04
You punch in on a normal calculator, solving that equation, two equations, two unknowns, you will get basically one over zero.
03:14
Basically, it will give you no answer.
03:17
An error or infinity, you know, think about infinity.
03:20
It gives you an error.
03:21
And so on.
03:22
That's because the calculators are rounding off.
03:24
Now, if there might be some calculators out there, especially as the years go by, they can handle that intrinsically to a certain point.
03:32
That's fine.
03:32
If it does, it does...