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Problem 111 Medium Difficulty

An astronaut of mass 210 $\mathrm{kg}$ including his suit and jet pack wants to acquire a velocity of 2.0 $\mathrm{m} / \mathrm{s}$ to move back toward his space shuttle. Assuming the jet pack can eject gas with a velocity of $35 \mathrm{m} / \mathrm{s},$ what mass of gas will need to be ejected?


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Physics 101 Mechanics

Physics for Scientists and Engineers with Modern Physics

Chapter 9

Linear Momentum

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Video Transcript

Okay, so does Chapter nine. Problem 1 11 So it's as Anne Ashman, out of a mass to 10 kilograms including a soup and jetpack, wants to require a velocity two years, percent it to move back towards space travel. Assuming the jet pack, can you just inject gas with Ava last year of 35 meters per second? What mass gas We need to be injected. Okay, but we know that we can take a use equation. 9 19 this equation. Cool. Then we can rearrange this now. It's so for our separate variables and see that you have TV over the relative velocity because tm over and since the relative velocity of gap the gas here, these are the same and that's a constant cannot integrate both sides. And we see that the final over the relative calls the natural log of final over initial mass. You can rewrite this as a queen is Ah, equation for mass were in final cool seat in the shoulder, times the exponential of the overview gas. Okay, so now we can figure out what the master of the objective is. Mass of the ejected is in minus and final or in missile. That was initial times in the file. More speed over G. Do this to your killer grandsons. One minus you. Final C was two meters per second over. The gas was 35 feet is exponential of that, we get roughly 12 kilograms. That's how much gas we need to sit down. Cool.

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