Question

An atom moving at its root-mean-square speed at $20^{\circ} \mathrm{C}$ has a wavelength of 3.28 $10^{-11} \mathrm{~m}$. Identify the atom.

   An atom moving at its root-mean-square speed at $20^{\circ} \mathrm{C}$ has a wavelength of 3.28 $10^{-11} \mathrm{~m}$. Identify the atom.
 
Chemistry
Chemistry
Raymond Chang, Jason… 14th Edition
Chapter 7, Problem 110 ↓
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An atom moving at its root-mean-square speed at $20^{\circ} \mathrm{C}$ has a wavelength of 3.28 $10^{-11} \mathrm{~m}$. Identify the atom.
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Transcript

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00:01 All right, so in this equation, or this question, we're going to need to combine a few equations.
00:07 So the root mean square velocity equation, is where velocity is equal to square root of three times r, which we're going to say is 8 .314, and then times the temperature in kelvin.
00:34 So we know that it says 20 degrees that's going to be 293 degrees divided by the mass of the particle which is what we need times abogadro's number which is 6 .02 times 10 to the 23rd okay so the other equation we're going to use is de brogley's equation where which says that the velocity so we can go ahead and put this equal velocity particle is equal to plank's constant divided by the mass of the particle times its wavelength.
01:17 So we'll go ahead and plug this in for the wavelength 2b says 3 .28 times 10 to the negative 11 meters.
01:38 And then we'll go ahead and say actually write out plank's constant, which is 6 .63 times 10 to the negative 34.
01:50 So when we go ahead and solve all this out, we get that the mass of the particle, in this case the atom, is 3 .36 times 10 to the negative 26 kilograms per atom...
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