00:01
So now we're going to work on problem 77 from chapter 13.
00:06
In this problem, we're told that we have, we're making an anti -freeze mixture by mixing equal volumes of ethylene glycol and water.
00:22
So we're given some information, the density of ethylin glycol and water and the molar mass of ethylin glycol, and we need to calculate volume percent, mass percent, molarity, molality, and mole fraction.
00:35
We're also given the density of the mixture.
00:40
So we're going to need several different parameters to calculate all these concentrations.
00:46
So first we should calculate the mass of ethylene glycol.
00:52
So we're told that they mix equal volumes of this ethlyn glycol and water.
01:00
It does tell us what the volumes are so we can select something that's convenient.
01:05
End.
01:07
So we can choose one liter for each volume.
01:13
So one liter of ethylin glycol.
01:16
And we can convert this to mass first by converting to milliliters, because the density value is given in grams per milliliter, and then multiplying by the density.
01:40
So milliliters and liters cancel, and we get a value of 11, 14 grams.
01:48
Of ethylene glycol.
01:54
So next we can calculate the mass of water.
01:59
The volume that we're given, or the volume that we chose, is one liter.
02:07
We go through exactly the same process.
02:24
The value of density that we're given for water is 1 .00 grams per milliliter.
02:31
So one liter of h2o is a thousand grams of h2o.
02:45
So to calculate all these concentrations, we're going to need moles of each of these solutions, each of these constituents of solutions.
02:55
So moles of ethylin glycol is equal to the mass, which we calculated, times the molar, or divided by the molar mass, which is 68 .02.
03:16
So we have a value of, it's 62 .07.
03:28
Read from the problem incorrectly.
03:31
And so that gives a value of 17 .947 moles.
03:39
We can do the same thing for water.
03:47
We have a mass of 1 ,000 grams.
03:51
We divide by the molar mass, which is 18 .02 grams per mole.
03:57
And we get a value of 55 .494 moles...