Question

An automobile driver increases the speed at a constant rate from $25 \mathrm{~km}$ 'h to $55 \mathrm{~km} / \mathrm{h}$ in $0.50 \mathrm{~min}$. A bicycle rider speeds up at a constant rate from rest to $30 \mathrm{~km} / \mathrm{h}$ in $0.50 \mathrm{~min}$. What are the magnitudcs of (a) the driver's acceleration and (b) the rider's acceleration?

Name: Problem 109, Chapter 2: Fundamentals of Physics
Uploaded: 2021-09-16T14:29:44-08:00
Duration: 2 min 22 s
Channel: Km Neeraj
Description: An automobile driver increases the speed at a constant rate from 25 km 'h to 55 km / h in 0.50 min. A bicycle rider speeds up at a constant rate from rest to 30 km / h in 0.50 min. What are the magnitudcs of (a) the driver's acceleration and (b) the rider's acceleration?

   An automobile driver increases the speed at a constant rate from $25 \mathrm{~km}$ 'h to $55 \mathrm{~km} / \mathrm{h}$ in $0.50 \mathrm{~min}$. A bicycle rider speeds up at a constant rate from rest to $30 \mathrm{~km} / \mathrm{h}$ in $0.50 \mathrm{~min}$. What are the magnitudcs of (a) the driver's acceleration and (b) the rider's acceleration?

Fundamentals of Physics

David Halliday,… 11th Edition

Chapter 2, Problem 109

Instant Answer

Solved by Expert Km Neeraj

09/16/2021

Step 1

We know that 1 km/h = 0.278 m/s. So, the initial speed of the car is $25 \mathrm{~km/h} = 25 \times 0.278 = 6.95 \mathrm{~m/s}$ and the final speed is $55 \mathrm{~km/h} = 55 \times 0.278 = 15.29 \mathrm{~m/s}$. The time taken is $0.50 \mathrm{~min} = 0.50 \times Show more…

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An automobile driver increases the speed at a constant rate from $25 \mathrm{~km}$ 'h to $55 \mathrm{~km} / \mathrm{h}$ in $0.50 \mathrm{~min}$. A bicycle rider speeds up at a constant rate from rest to $30 \mathrm{~km} / \mathrm{h}$ in $0.50 \mathrm{~min}$. What are the magnitudcs of (a) the driver's acceleration and (b) the rider's acceleration?

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Key Concepts

Acceleration

Acceleration is the rate at which an object's velocity changes over time. It is a vector quantity, meaning it has both magnitude and direction. In problems involving constant acceleration, the change in velocity divided by the time interval remains the same throughout the motion.

Unit Conversion

For consistency in solving physics problems, quantities must often be converted into compatible units. This includes converting speeds from kilometers per hour to meters per second and time from minutes to seconds, which is essential for applying standard kinematics equations correctly.

Uniform (Constant) Acceleration

Uniform or constant acceleration refers to motion where the acceleration remains fixed over time. This concept allows the use of simple formulas, such as acceleration equals the change in velocity divided by the change in time, to solve problems involving linear motion.

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