Question
An automobile engine develops $100 \mathrm{kw}$ when rotating at a speed of 1800 r.p.m. what torque does it deliver?$\{\mathrm{A}\} 350 \mathrm{Nm} \quad\{\mathrm{B}\} 440 \mathrm{Nm}$\{C $\} 531 \mathrm{Nm} \quad\{\mathrm{D}\} 628 \mathrm{Nm}$
Step 1
We know that 1 kilowatt is equal to 1000 watts. So, the power $P$ is $100 \times 1000 = 100000$ watts. Show more…
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An automobile engine develops $100 \mathrm{~kW}$ when rotating at a speed of $1800 \mathrm{rev} / \mathrm{min}$. What torque does it deliver (a) $350 \mathrm{~N}-\mathrm{m}$ (b) $440 \mathrm{~N}-\mathrm{m}$ (c) $531 \mathrm{~N}-\mathrm{m}$ (d) $628 \mathrm{~N}-\mathrm{m}$
An automobile engine develops $100 \mathrm{~kW}$ when rotating at a speed of $1800 \mathrm{rpm}$. The torque delivered by the engine is (a) $\frac{10^{2}}{6 \pi} \mathrm{N} \mathrm{m}$ (b) $\frac{10^{4}}{6 \pi} \mathrm{Nm}$ (c) $\frac{10^{6}}{6 \pi} \mathrm{N} \mathrm{m}$ (d) $\frac{10^{8}}{6 \pi} \mathrm{N} \mathrm{m}$
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