Question
An automobile tire has a volume of 0.0150 $\mathrm{m}^{3}$ on a cold day when the temperature of the air in the tire is $5.0^{\circ} \mathrm{C}$ and atmospheric pressure is 1.02 atm. Under these conditions the gauge pressure is measured to be 1.70 atm (about 25 $\mathrm{lb} / \mathrm{in.} .$ ). After the car is driven on the highway for 30 min, the temperature of the air in the tires has risen to $45.0^{\circ} \mathrm{C}$ and the volume has risen to 0.0159 $\mathrm{m}^{3}$ . What then is the gauge pressure?
Step 1
The initial pressure is the sum of the atmospheric pressure and the gauge pressure. So, we have: \[P_1 = P_{atm} + P_{gauge} = 1.02 \, \text{atm} + 1.70 \, \text{atm} = 2.72 \, \text{atm}\] Show more…
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An automobile tire has a volume of 0.0150 m$^3$ on a cold day when the temperature of the air in the tire is 5.0$^\circ$C and atmospheric pressure is 1.02 atm. Under these conditions the gauge pressure is measured to be 1.70 atm (about 25 lb/in.$^2$). After the car is driven on the highway for 30 min, the temperature of the air in the tires has risen to 45.0$^\circ$C and the volume has risen to 0.0159 m$^3$. What then is the gauge pressure?
$\bullet$ An automobile tire has a volume of 0.0150 $\mathrm{m}^{3}$ on a cold day when the temperature of the air in the tire is $5.0^{\circ} \mathrm{C}$ and atmospheric pressure is 1.02 atm. Under these conditions, the gauge pressure is measured to be 1.70 atm (about 25 $\mathrm{lb} / \mathrm{in}^{2}$ ). After the car is driven on the highway for 30 min, the temperature of the air in the tires has risen to $45.0^{\circ} \mathrm{C}$ and the volume to 0.0159 $\mathrm{m}^{3} .$ What is the gauge pressure at that time?
An automobile tire has a volume of 0.0150 $\mathrm{m}^{3}$ on a cold day when the temperature of the air in the tire is $5.0^{\circ} \mathrm{C}$ and atmospheric pressure is 1.02 $\mathrm{atm}$ . Under these conditions the gauge pressure is measured to be 1.70 atm (about 25 Ib $/$ in. $^{2}$.) After the car is driven on the highway for 30 $\mathrm{min}$ , the temperature of the air in the tires has risen to $45.0^{\circ} \mathrm{C}$ and the volume has risen to 0.0159 $\mathrm{in}^{3} .$ Whatthen is the gauge pressure?
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