Question
An Earth Satellite An Earth satellite moves in a circular orbit $640 \mathrm{~km}$ above Earth's surface with a period of $98.0 \mathrm{~min}$. What are(a) the speed and (b) the magnitude of the centripetal acceleration of the satellite?
Step 1
The radius of the Earth is $6.38 \times 10^6$ m and the satellite is $640,000$ m above the Earth's surface. So, the radius of the orbit is the sum of these two distances. \[ r = 6.38 \times 10^6 m + 640,000 m = 7.02 \times 10^6 m \] Show more…
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