a. 7.50b. 0.944 m

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Christina K.

Rutgers, The State University of New Jersey

Other Schools

Jared E.

University of Winnipeg

Video Transcript

So in this problem, the person has two lenses of different powers. One is positive, 1.2 doctors and the other one is positive. Nine doctors. So from here, we can actually find the focal length of both of the lenses, which is basically the reciprocal of the power of each. And I have already shown the focal length F one enough to hear. So if one is going to be a zero point 833 0.833 meter and after is going to be 0.111 meter. So if the sailor wants to be like telescope, that actually f one has to be the focal length of the objective. Okay. Hey, 33 and F two has to be the focal length of the eyepiece. Now, from here, we can easily find the magnification for party. So far, for part a, the magnification of the angular magnification of the telescope is for collective objective. Over focal length off eyepiece. This is going to be a 0.833 over 0.111 And this will give me a 7.5. All right now for part B the length of the telescope basically would be the focal length of the objective and focal length of the I Piss, which is 0.833 plus 0.111 meters because 0.944 meters.

University of Wisconsin - Milwaukee
Christina K.

Rutgers, The State University of New Jersey

Other Schools

Jared E.

University of Winnipeg